McDougal Littell Algebra 2, Chapter 3, 3.2, Section 3.2, Problem 44

The equations 3x - 6y = 20 and -11x + 10y = 5 have to be solved.
From 3x - 6y = 20
3x = 20 + 6y
x = 20/3 + 2y
Substitute in -11x + 10y = 5
-11*(20/3 + 2y) + 10y = 5
-220/3 - 22y + 10y = 5
12y = -235/3
y = -235/36
x = 20/3 + -470/36 = -115/18
The solution of the equations is x = -115/18 and y = -235/36