Tuesday, June 27, 2017

Single Variable Calculus, Chapter 2, 2.3, Section 2.3, Problem 29

Determine the limt0(1t1+t1t), if it exists.


limt0(1t1+t1t)=limt011+tt1+t Get the LCD.limt011+tt1+t1+1+t1+1+t=limt01(1+t)t(1+t)(1+1+t) Multiply the numerator and the denominator by 1+1+t and simplify.limt01(1+t)(1+1+t)=1(1+0)(1+1+0)=1(1)(1+1)=1(1)(2)=12 Substitute value of t and simplifylimt0(1t1+t1t)=12

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