Sketch the graph of a function that satisfies all of the given conditions
f′(1)=f′(−1)=0, f′(x)<0 if |x|<1,
f′(x)>0 if 1<|x|<2, f′(x)=−1 if |x|>2,
f″ if -2 < x < 0, inflection point (0,1)
The first statement tells us that there is an horizontal tangents at x = 1 and x = -1 since the slope is zero. The second statement tells us that the slope is positive at interval. 1 < |x| < 2 and slope of -1 at interval |x| > 2. The last statement tells us that the inflection point should be at (0,1) and should have a downward concavity at interval -2 < x < 0
Thursday, October 1, 2015
Single Variable Calculus, Chapter 4, 4.3, Section 4.3, Problem 22
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