McDougal Littell Algebra 2, Chapter 3, 3.1, Section 3.1, Problem 75

(2, -6), (-1, 7)
To solve this, we can substitute the x and y values into the equation to see if they are solutions. First, let's substitute the (2,-6).
6(2)+0.5(-6)<=-5
12-3<=-5
9<=-5
9 is not less than or equal to -5. Therefore, (2,-6) is NOT a solution of the inequality. Now we substitute the other x and y value which are (-1,7) to check if they are solutions.
6(-1)+0.5(7)<=-5
-6+3.5<=-5
-2.5<=-5
-2.5 is not less than or equal to -5. This means that (-1,7) are also not solutions of the inequality. Therefore, both (2,-6) and (-1,7) are NOT solutions for this inequality.