Beginning Algebra With Applications, Chapter 5, 5.2, Section 5.2, Problem 110

Graph $4x+3y = 12$ by using $x$- and $y$-intercepts

$x$-intercept:


$\begin{equation} \begin{aligned} 4x+3y =& 12 && \text{Given equation} \\ 4x + 3(0) =& 12 && \text{To find the $x$-intercept, let } y = 0 \\ 4x =& 12 && \text{Divide by } 4 \\ x =& 3 && \end{aligned} \end{equation}$


The $x$-intercept is $(3,0)$

$y$-intercept:


$\begin{equation} \begin{aligned} 4x+3y =& 12 && \text{Given equation} \\ 4(0) +3y =& 12 && \text{To find the $y$-intercept, let } x=0 \\ 3y =& 12 && \text{Divide by } 3 \\ y =& 4 && \end{aligned} \end{equation}$



The $y$-intercept is $(0,4)$

Graph the ordered pairs $(3,0)$ and $(0,4)$. Draw a straight line through the points.