Glencoe Algebra 2, Chapter 2, 2.3, Section 2.3, Problem 43

The line which we needed is perpendicular to a line whose slope is (-1) .
the product of the slopes of two lines which are perpendicular is equal to -1
let the slope of the line which we need to find be m_1 and the slope of the other line be m_2 = -1
so ,
m_1 * m_2 = -1
=> m_1 = -1/(m_2) = -1 /(-1) = 1
so , m_1 = 1
and the line of slope m_1 passes through the point (-2,2)
then the line is
y = mx+c
=> y = (1)x +c
as it passes through (x,y)=(-2,2) so
=> 2= (1)(-2) +c
=> 2= -2 +c
=> 2+2 = c
=> c = 4
so the equation of the line is y= x+ 4 and the graph plotted is as follows in the attachments. the point (-2,2) is spotted with a blue dot.