The function y = sqrt(r^2 - x^2) describes a circle centred on the origin with radius r .
If we revolve this function in the range 0 <=x <=a , a < r about the y-axis we obtain a surface of revolution that is specifically a zone of a sphere with radius r .
A zone of a sphere is the surface area between two heights on the sphere (surface area of ground between two latitudes when thinking in terms of planet Earth).
For the range of interest 0 <=x<=a , the zone of interest is specifically a spherical cap on the sphere of radius r . The range of interest for y corresponding for that for x is sqrt(r^2-a^2) <= y <= r .
The equivalent on planet Earth of the surface area of such a spherical cap could be, for example, the surface area of a polar region. This of course makes the simplifying assumption that the Earth is perfectly spherical, which is not the case.
To calculate the surface area of this cap of a sphere with radius r , we require the formula for the surface area of revolution of a function x = f(y) (note, I have swapped the roles of x and y for convenience, as the formula is typically written for rotating about the x-axis rather than about the y-axis as we are doing here).
The formula for the surface area of revolution of a function x = f(y) rotated about the y-axis in the range alpha <= y <= beta is given by
A = int_alpha^beta 2pi x sqrt(1+ ((dx)/(dy))^2) \quad dy
Here, we have that alpha = sqrt(r^2 - a^2) and beta = r . Also, we have that
(dx)/(dy) = -y/sqrt(r^2-y^2)
so that the cap of interest has areaA = int_sqrt(r^2-a^2)^r 2pi sqrt(r^2-y^2) sqrt(1+(y^2)/(r^2-y^2)) \quad dy
which can be simplified to
A =2pi int_sqrt(r^2-a^2)^r sqrt((r^2-y^2) + y^2) \quad dy
= 2pi int_sqrt(r^2-a^2)^r r dy = 2pi r y |_sqrt(r^2-a^2)^r = 2pi r (r -sqrt(r^2-a^2))
So that the zone (specifically cap of a sphere) area of interest A =
= pi (2r^2 - 2rsqrt(r^2-a^2))
This marries up with the formula for the surface area of a spherical cap
A = pi (h^2 + a^2)
where a is the radius at the base of the spherical cap and h is the height of the cap. The value of h is the range covered on the y-axis, so that
h = r -sqrt(r^2 - a^2) and
h^2 = 2r^2 - 2rsqrt(r^2 - a^2) - a^2 and
h^2 + a^2 = 2r^2 - 2rsqrt(r^2 - a^2)
http://mathworld.wolfram.com/SphericalCap.html
http://mathworld.wolfram.com/SurfaceofRevolution.html
https://www.scientificamerican.com/article/earth-is-not-round/?redirect=1&error=cookies_not_supported&code=e6764ca4-36e8-4b78-b577-bf04205f7a98
Tuesday, June 25, 2019
Find the area of the zone of a sphere formed by revolving the graph of y=sqrt(r^2-x^2) , 0
Subscribe to:
Post Comments (Atom)
Why is the fact that the Americans are helping the Russians important?
In the late author Tom Clancy’s first novel, The Hunt for Red October, the assistance rendered to the Russians by the United States is impor...
-
There are a plethora of rules that Jonas and the other citizens must follow. Again, page numbers will vary given the edition of the book tha...
-
The poem contrasts the nighttime, imaginative world of a child with his daytime, prosaic world. In the first stanza, the child, on going to ...
-
The given two points of the exponential function are (2,24) and (3,144). To determine the exponential function y=ab^x plug-in the given x an...
-
The play Duchess of Malfi is named after the character and real life historical tragic figure of Duchess of Malfi who was the regent of the ...
-
The only example of simile in "The Lottery"—and a particularly weak one at that—is when Mrs. Hutchinson taps Mrs. Delacroix on the...
-
Hello! This expression is already a sum of two numbers, sin(32) and sin(54). Probably you want or express it as a product, or as an expressi...
-
Macbeth is reflecting on the Weird Sisters' prophecy and its astonishing accuracy. The witches were totally correct in predicting that M...
No comments:
Post a Comment