Chris is saving for his retirement by making regular deposits into a $410k$ plan. As his salary rises, he finds that he can deposit increasing amounts each year. Between the years $1995$ and $2008$, the annual amount(in dollars) that he deposited was given by the function $D(t) = 3500 + 15 t^2$, where $t$ represents the year of the deposit measured fron the store of the plan.
a.) Find $D(0)$ and $D(15)$. What do these values represent?
b.) At what year will he deposit $\$17,000$? Assuming that his deposits continue to be modeled by the function $D$.
c.) Determine the average rate of change of $D$ between $t = 0$ and $t = 15$. What does this number represent?
$
\begin{equation}
\begin{aligned}
\text{a.) } D(0) &= 3500 + 15 (0) ^2 &&& D(15) &= 3500+15(15)^2\\
\\
&= 3500 &&& &= 6875
\end{aligned}
\end{equation}
$
$D(0)$ represents the amount of Chris deposit from the start of the plan in 1995. On the other hand, $D(15)$ represents the amount of Chris deposit 15 years after the start of the plan, in 2010.
b.) $D = 17,000$ then
$
\begin{equation}
\begin{aligned}
17,000 &= 3500+15t^2 && \text{Solve for } t \text{, subtract 3500}\\
\\
15t^2 &= 13,500 && \text{Divide }15\\
\\
t^2 &= 900 && \text{Take the square root}\\
\\
t &= \pm 30 && \text{Choose } t > 0
\end{aligned}
\end{equation}
$
It shows that in the year $2025$, Chris will deposit $\$17,000$
c.) Recall that the formula for average rate is
$\displaystyle \frac{f(b) - f(a)}{b-a}$
Thus,
$\displaystyle \frac{D(15) - D(0)}{15 - 0} = \frac{6875-3500}{15} = 225$
This number represents the average rate of increase of Chris deposit between the years 1945 and 2010.
Saturday, October 20, 2018
College Algebra, Chapter 3, Review Exercises, Section Review Exercises, Problem 60
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