Suppose that the model for the length of daylight (in hours) in Philadelphia on the tth day of the year us L(t)=12+2.8sin[dπ365(t−80)]. Use this model to compare how the number of hours of daylight is increasing in Philadelphia on March 21 and May 21.
dLdt=2.8cos[2π365(t−80)](2π365)dLdt=5.6π365cos[2π365(t−80)]On March 21, the 80th day of the year,dLdt=5.6π365cos[2π365(80−80)]dLdt=0.0482 hours/ dayOn May 21, the 141st day of the year,dLdt=5.6π365cos[2π365(141−80)]dLdt=0.0240 hours/day
Friday, March 16, 2018
Single Variable Calculus, Chapter 3, 3.5, Section 3.5, Problem 78
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