Calculus: Early Transcendentals, Chapter 5, 5.3, Section 5.3, Problem 40

You need to evaluate the definite integral using the fundamental theorem of calculus, such that:
int_a^b f(u) du = F(b) - F(a)
int_1^2 (4+u^2)/(u^3) du = int_1^2 4/(u^3) du + int_1^2 (u^2)/(u^3) du
int_1^2 (4+u^2)/(u^3) du = 4int_1^2 (u^(-3)) du + int_1^2 1/u du
Using the formula int u^n = (u^(n+1))/(n+1)+ c yields:
4int_1^2 (u^(-3)) du = 4(u^(-2))/(-2) = -2/(u^2)|_1^2 = -2(1/2^2 - 1/1^2)
4int_1^2 (u^(-3)) du =-2(1/4 - 1) = -2*(-3/4) = 3/2
int_1^2 1/u du = ln u|_1^2 = ln 2 - ln 1 = ln 2
Hence, evaluating the definite integral, yields int_1^2 (4+u^2)/(u^3) du = 3/2 + ln 2.