Graph $3x-y = 6$ by using $x$- and $y$-intercepts
$x$-intercept:
$
\begin{equation}
\begin{aligned}
3x-y =& 6
&& \text{Given equation}
\\
3x - 0 =& 6
&& \text{To find the $x$-intercept, let } y = 0
\\
3x =& 6
&& \text{Divide by } 3
\\
x =& 2
&&
\end{aligned}
\end{equation}
$
The $x$-intercept is $(2,0)$
$y$-intercept:
$
\begin{equation}
\begin{aligned}
3x-y =& 6
&& \text{Given equation}
\\
3(0)-y =& 6
&& \text{To find the $y$-intercept, let } x=0
\\
-y =& 6
&& \text{Divide by } -1
\\
y =& -6
&&
\end{aligned}
\end{equation}
$
The $y$-intercept is $(0,-6)$
Graph the ordered pairs $(2,0)$ and $(0,-6)$. Draw a straight line through the points.
Saturday, October 19, 2019
Beginning Algebra With Applications, Chapter 5, 5.2, Section 5.2, Problem 108
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