McDougal Littell Algebra 2, Chapter 5, 5.2, Section 5.2, Problem 33

1. First, let's identify the a, b, and c in trinomial. aq^(2)+bq+c
a=1
b=-7
c=-10
We shouldn't be to concerned about 'a' since it is 1. And, 'b' is what the 2 numbers have to add up to. Last, but not least, 'c' is what the two factors need to multiply up to.
2. We now have to find 2 numbers whose product equals -10 and sum is -7. List out a couple combinations until you find your match.
(-10)(1)=-10 ; -10+1=-9
(5)(-2) = -10 ; 5+(-2)=-3
(-2)(5)= -10 ' -2+5=3
(-1)(10)=-10 ; -1+10=9
However, after listing out the possible combinations, there is no perfect match. Therefore, this equation is not factorable.