Precalculus, Chapter 6, 6.1, Section 6.1, Problem 18

The sine law indicates that in a triangle;
(sinA)/a =(sinB)/b =(sinC)/c
a,b,c are the lengths of the triangle and A,B,C are the opposite angles as shown in image.

(sinA)/a =(sinB)/b
sin60/9 = sinB/5
B = sin^(-1)(sin60xx5/9) = 28.76^0

Angle C = 180-28.76-60 = 91.24^0

(sinB)/b =(sinC)/c
c = (sin91.24xx5)/sin28.76 = 10.39

So the answers are;
Angle B = 28.76 deg
Angle C = 91.24 deg
Length c = 10.39 units