y=x/(1+e^(x^3)) , y=0 , x=2 Find the area of the region bounded by the graphs of the equations

If we have two function f(x) and g(x) we can find the area between the curves with the following formula.
A=int^b_a (f(x)-g(x))dx
Where f(x) is the upper function and g(x) is the lower function.
In this case let f(x)=x/(1+e^x^3), g(x)=0 and integrate from x=0 to x=2.
A=int^2_0 (x/(1+e^x^3)-0)dx
A=int^2_0 x/(1+e^x^3)dx
This integral may not have an analytical solution. So I'm just going to approximate the integral useing Simpsons rule.
A=int^2_0 x/(1+e^x^3)dx~~(Delta x)/3(y_0+4y_1+2y_2+4y_3+2y_4...+4y_(n-1)+y_n)
Where Delta x=(b-a)/n=2/n
Ill use 10 intervals, so n=10.
A=int^2_0 x/(1+e^x^3)dx~~0.287099
http://tutorial.math.lamar.edu/Classes/CalcI/AreaBetweenCurves.aspx

https://www.intmath.com/integration/6-simpsons-rule.php