Glencoe Algebra 2, Chapter 2, 2.4, Section 2.4, Problem 35

Given
the line is y = (2/3) x + 5
and the slope of the line is m_1 = 2/3
as we know that the slopes of two parallel lines are equal
let the slope of the required line is m_2
so ,
(m_1)=(m_2)= 2/3

and the required line passes through (4,6)

and slope m_2= 2/3
As,the slope-intercept form of a line is
y= mx+b
from the above we know m_2 = 2/3 , so the line equation is
y= ( 2/3)x+b --------------(1)
we need to find the value of b , as the line passes through the point
(x,y)= (4,6 ) , then on substituting we get
6 =(2/3)*(4)+b
=> b = 6-(8/3)= 10/3
so the equation of the line is
y= ( 2/3)x+(10/3)