Beginning Algebra With Applications, Chapter 6, 6.2, Section 6.2, Problem 64

Solve the system of equations: $
\begin{equation}
\begin{aligned}

1.25x - 0.01y =& 1.5 \\
0.24x - 0.02y =& -1.52

\end{aligned}
\end{equation}
$


$
\begin{equation}
\begin{aligned}

0.24x - 0.02y =& -1.52
\qquad \text{Solve equation 2 for } y
\\
\\
-0.02y =& -0.24x - 1.52
\\
\\
y =& \frac{-0.24x - 1.52}{-0.02}
\\
\\
y =& 12x+76

\end{aligned}
\end{equation}
$




$
\begin{equation}
\begin{aligned}

1.25x - 0.01y =& 1.5
\qquad \text{Substitute } 12x+76 \text{ for $y$ in equation 1}
\\
\\
1.25x-0.01 (12x+76) =& 1.5
\\
\\
1.25x - 0.12x - 0.76 =& 1.5
\\
\\
1.13x =& 1.5+0.76
\\
\\
1.13x =& 2.26
\\
\\
x =& 2

\end{aligned}
\end{equation}
$


Substitute the value of $x$ in equation 2


$
\begin{equation}
\begin{aligned}

y =& 12(2) + 76
\\
\\
y =& 24+76
\\
\\
y =& 100

\end{aligned}
\end{equation}
$


The solution is $(2,100)$.