y = 4x-x^2 , x = 0 , y=4 Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis.

To be able to use the Shell method, a rectangular strip from the bounded plane region should be parallel to the axis of revolution. By revolving multiple rectangular strip, it forms infinite numbers of this hollow pipes or representative cylinders.
 In this method, we follow the formula: V = int_a^b (length * height * thickness)
or V = int_a^b 2pi * radius*height*thickness
where:
radius (r)= distance of the rectangular strip to the axis of revolution
height (h) = length of the rectangular strip
thickness = width  of the rectangular strip  as dx or dy .
For the bounded region, as shown on the attached image, the rectangular strip is parallel to y-axis (axis of rotation). We can let:
r=x
h=f(x) or h=y_(above)-y_(below)
h =4-(4x-x^2) = 4-4x+x^2
thickness = dx
 Boundary values of x from a=0 to b =2 .
Plug-in the values on V = int_a^b 2pi * radius*height*thickness, we get:
V = int_0^2 pi*x*(4 -4x+x^2)*dx
Simplify: V = int_0^2 pi(4x -4x^2+x^3)dx
Apply basic integration property: int c*f(x) dx = c int f(x) dx
V = 2pi[ int_0^2(4x -4x^2+x^3)dx]
Apply basic integration property:int (u+-v+-w)dy = int (u)dy+-int (v)dy+-int(w)dy  to be able to integrate them separately using Power rule for integration: int x^n dx = x^(n+1)/(n+1).
V = 2pi[ int_0^2(4x) dx -int_0^2(4x^2)dx+int_0^2(x^3)dx]
V = 2pi[ 4*x^2/2 -4*x^3/3+x^4/4]|_0^2
V = 2pi[ 2x^2 -(4x^3)/3+x^4/4]|_0^2
Apply the definite integral formula: int _a^b f(x) dx = F(b) - F(a) .
V =2 pi[ 2(2)^2 -(4(2)^3)/3+(2)^4/4]-2pi[ 2(0)^2 -(4(0)^3)/3+(0)^4/4]
V = 2pi[ 8-32/3+4] - 2pi[0-0+0]
V = 2pi[ 4/3] -0
V = (8pi)/3 or 8.38 (approximated value)