Monday, January 2, 2017

Calculus and Its Applications, Chapter 1, 1.2, Section 1.2, Problem 20

Determine the limx5x225x25 by using the Theorem on Limits of Rational Functions.
When necessary, state that the limit does not exist.


limxx225x25=limx5(x+5)(x5)x5Factor the numerator by applying the rule for difference of square=limx5(x+5)Cancel out like terms=limx5x+limx55The limit of a sum is the sum of the limits=limx5x+5The limit of a constant is the constant=5+5Substitute 5=10

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