Determine the limx→5x2−25x2−5 by using the Theorem on Limits of Rational Functions.
When necessary, state that the limit does not exist.
limx→x2−25x2−5=limx→5(x+5)(x−5)x−5Factor the numerator by applying the rule for difference of square=limx→5(x+5)Cancel out like terms=limx→5x+limx→55The limit of a sum is the sum of the limits=limx→5x+5The limit of a constant is the constant=5+5Substitute 5=10
Monday, January 2, 2017
Calculus and Its Applications, Chapter 1, 1.2, Section 1.2, Problem 20
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