Suppose the individual demand equation for bananas is Q_d= 50 - 10P_x and the individual supply equation is expressed as Q_s= 10P_x. a. Construct a demand and supply schedule. b. On the same set of axes, graph the demand and supply curve. c. Determine the equilibrium point graphically and mathematically.

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c. The simplest part is finding the equilibrium point "mathematically" (it is better to say "algebraically"). For this, we have to equate Q_d and Q_s: 50-10P_x = 10P_x. This is a simple linear equation that becomes 50 = 20 P_x and P_x = 2.5 (units are probably $/kg). The supply and demand are both equal to 25 at this point. We obtain the same result looking at a graph. b. The graphs are simple, too. They are both straight lines. Please look at this link: https://www.desmos.com/calculator/zngt7rj9fr a. The schedule is simply a table that lists some possible price (P_x) values and the corresponding Q_d and Q_s values. We may choose the step between the P_x values. Let it be 1$/kg:
P_x    Q_d    Q_s
  1       40      10
  2       30      20
  3       20      30
  4       10      40
You can extend this table with P_x values 0.5, 1.5 and so on.