Determine the equation of the line that is perpendicular to the line x−2y=−5 containing the point (0,4). Express your answer using the general form or the slope intercept form of the equation of a line, which ever you prefer.
We first write the given equation in slope intercept form to find its slope
x−2y=−5−2y=−x−5Solve for yy=12x+52Write in the form y=mx+b
The slope is 12. Any line perpendicular to this line will have slope −2. The point (0,4) is on the line with slope −2, we use the point slope form to find this equation.
y−y1=m(x−x1)Point Slope Formy−4=−2(x−0)Substitute m=−2,x=0 and y=4y=−2x+4Slope Intercept Formor2x+y=4General Form
Tuesday, September 2, 2014
Precalculus, Chapter 1, 1.3, Section 1.3, Problem 68
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