Given the graph of $f$
a.) Determine each limit if it exist. If the limit does not exist. Explain why.
$\qquad$ i.) $\displaystyle \lim \limits_{x \to 2^+} f(x)$
$\qquad \qquad $ Referring to the given graph. $\displaystyle \lim \limits_{x \to 2^+} f(x) = 3$
$\qquad$ ii.) $\displaystyle \lim \limits_{x \to -3^+} f(x)$
$\qquad \qquad $ Referring to the given graph $\displaystyle \lim \limits_{x \to -3^+} f(x) = 0$
$\qquad$ iii.) $\displaystyle \lim \limits_{x \to -3} f(x)$
$\qquad \qquad $ Referring to the given graph $\displaystyle \lim \limits_{x \to -3} f(x)$ does not exist because left and right hand limits approaches different values.
$\qquad$ iv.) $\displaystyle \lim \limits_{x \to 4} f(x)$
$\qquad \qquad $ Referring to the given graph $\displaystyle \lim \limits_{x \to 4} f(x) = 2$
$\qquad$ v.) $\displaystyle \lim \limits_{x \to 0} f(x)$
$\qquad \qquad $ Referring to the given graph $\displaystyle \lim \limits_{x \to 0} f(x) = \infty$
$\qquad$ vi.) $\displaystyle \lim \limits_{x \to 2^-} f(x)$
$\qquad \qquad $ Referring to the given graph $\displaystyle \lim \limits_{x \to 2^-} f(x) = -\infty$
b.) Indicate the equations of the vertical asymptotes.
$\qquad$ The vertical asymptotes happens when the value of $x$ is not defined. Referring to the graph, the vertical asymptotes are $x = 0, x = 2$
c.) Where is $f$ discontinuous? Explain.
$\qquad$ $f$ is discontinuous at $x = -3$ because of jump discontinuity. Also, the function is discontinuous at $x = 0$ and $x = 2$ because of infinite discontinuity. Lastly, $f$ is discontinuous at $x = 4$ because of removable discontinuity.
Saturday, July 7, 2018
Single Variable Calculus, Chapter 2, Review Exercises, Section Review Exercises, Problem 1
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