Given the graph of f
a.) Determine each limit if it exist. If the limit does not exist. Explain why.
i.) lim
\qquad \qquad Referring to the given graph. \displaystyle \lim \limits_{x \to 2^+} f(x) = 3
\qquad ii.) \displaystyle \lim \limits_{x \to -3^+} f(x)
\qquad \qquad Referring to the given graph \displaystyle \lim \limits_{x \to -3^+} f(x) = 0
\qquad iii.) \displaystyle \lim \limits_{x \to -3} f(x)
\qquad \qquad Referring to the given graph \displaystyle \lim \limits_{x \to -3} f(x) does not exist because left and right hand limits approaches different values.
\qquad iv.) \displaystyle \lim \limits_{x \to 4} f(x)
\qquad \qquad Referring to the given graph \displaystyle \lim \limits_{x \to 4} f(x) = 2
\qquad v.) \displaystyle \lim \limits_{x \to 0} f(x)
\qquad \qquad Referring to the given graph \displaystyle \lim \limits_{x \to 0} f(x) = \infty
\qquad vi.) \displaystyle \lim \limits_{x \to 2^-} f(x)
\qquad \qquad Referring to the given graph \displaystyle \lim \limits_{x \to 2^-} f(x) = -\infty
b.) Indicate the equations of the vertical asymptotes.
\qquad The vertical asymptotes happens when the value of x is not defined. Referring to the graph, the vertical asymptotes are x = 0, x = 2
c.) Where is f discontinuous? Explain.
\qquad f is discontinuous at x = -3 because of jump discontinuity. Also, the function is discontinuous at x = 0 and x = 2 because of infinite discontinuity. Lastly, f is discontinuous at x = 4 because of removable discontinuity.
Saturday, July 7, 2018
Single Variable Calculus, Chapter 2, Review Exercises, Section Review Exercises, Problem 1
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