Monday, January 29, 2018

College Algebra, Chapter 1, 1.6, Section 1.6, Problem 90

The equation T=600,000x2+300 represents the temperature in C at a distance x refers from the center of the fire in the vicinity of a bonfire. At what range of distance from the fire's center was the temperature less than 50C

600,000x2+300<500model600,000x2+300500<0Subtract 500600,000500x2150,000x2+300<0Common Denominators500x2+450,000x2+300<0Simplify the numerator500(x2900)x2+300<0Factor out -500x2900x2+300>0Divide both sides by -500(x+30)(x30)x2+300>0Difference of squares


The real solution will be x30>0. It shows that if the distance of the man from the fire is greater than 30m, the temperature will be less than 500C

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