The equation T=600,000x2+300 represents the temperature in ∘C at a distance x refers from the center of the fire in the vicinity of a bonfire. At what range of distance from the fire's center was the temperature less than 50∘C
600,000x2+300<500model600,000x2+300−500<0Subtract 500600,000−500x2−150,000x2+300<0Common Denominators−500x2+450,000x2+300<0Simplify the numerator−500(x2−900)x2+300<0Factor out -500x2−900x2+300>0Divide both sides by -500(x+30)(x−30)x2+300>0Difference of squares
The real solution will be x−30>0. It shows that if the distance of the man from the fire is greater than 30m, the temperature will be less than 500∘C
Monday, January 29, 2018
College Algebra, Chapter 1, 1.6, Section 1.6, Problem 90
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