Beginning Algebra With Applications, Chapter 5, 5.2, Section 5.2, Problem 112

Graph $3x+ y = -5$ by using $x$- and $y$-intercepts

$x$-intercept:


$\begin{equation} \begin{aligned} 3x+ y =& -5 && \text{Given equation} \\ 3x+ 0 =& -5 && \text{To find the $x$-intercept, let } y = 0 \\ 3x =& -5 && \text{Divide by } 3 \\ x =& \frac{-5}{3} && \end{aligned} \end{equation}$


The $x$-intercept is $\displaystyle \left( \frac{-5}{3}, 0 \right)$

$y$-intercept:


$\begin{equation} \begin{aligned} 3x+ y =& -5 && \text{Given equation} \\ 3(0)+ y =& -5 && \text{To find the $y$-intercept, let } x=0 \\ y =& -5 && \end{aligned} \end{equation}$



The $y$-intercept is $(0,-5)$

Graph the ordered pairs $\displaystyle \left( \frac{-5}{3}, 0 \right)$ and $(0,-5)$. Draw a straight line through the points.