Sunday, February 17, 2013

Single Variable Calculus, Chapter 2, 2.4, Section 2.4, Problem 10

Find a number δ by using a graph such that if 5<x<5+δ then x2x5>100


We can determine the value of δ by getting the point of intersection of the curve and the line y=100. As shown in the graph:






x2x5=100x2=100x5x2100x5=0

Solving for x,
x=5.0659


Hence, the value of δ is...


5+δxδx5δ5.06595δ0.0659

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