If 1.806x10^24 molecules of N2 are produced, how many atoms of sodium metal are also produced?

I am assuming that you are referring to the production of nitrogen gas by thermal decomposition of sodium azide as per the following chemical reaction:
2NaN_3 -> 2Na + 3N_2
In this reaction, the products are sodium atoms and nitrogen molecules.
Remember that each mole of a substance contains an Avogadro's number of particles. In this case, we can say that 1 mole of nitrogen will contain 6.023 x 10^23 molecules. We are given that 1.806 x 10^24 molecules are produced.
In other words, 3 moles (= 1.806x10^24 / 6.023x10^23) of nitrogen is produced.
From the chemical reaction, 3 moles of nitrogen is produced along with 2 moles of sodium by using 2 moles of sodium azide.
Hence, along with the production of 3 moles ( or 1.806 x 10^24 molecules) of nitrogen, 2 moles of sodium will also be produced.
This is equal to 1.2046 x 10^24 (= 2 x 6.023 x 10^23) atoms of sodium.
Hope this helps.