Precalculus, Chapter 4, 4.4, Section 4.4, Problem 16

Given the point on the terminal (x,y) = (-4,10)
so,
x= -4, y= 10
then r=sqrt((-4)^2+(-10)^2) =sqrt(16+100) =sqrt(116)
then
let theta be the angle
then
sin theta = y/r = 10/sqrt(116)
cos theta =x/r = -4/sqrt(116)
tan theta = y/x = 10/-4 = -10/4
csc theta = r/y = sqrt(29)/10 = sqrt(116)/10
sec theta = r/x =sqrt(29)/-4 = -sqrt(116)/4
cot theta = x/y = -4/10