Differentiate the function y=√x(x−1) We have y=x12(x−1)y=x12+1−x12=x32−x12 So, dydx=ddx(x32−x12)=ddx(x32)−ddx(x12)=32⋅x32−1−12x12−1=32x12−12x−12or=32√x−12√x
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