Saturday, August 24, 2019

Intermediate Algebra, Chapter 1, 1.3, Section 1.3, Problem 92

Evaluate the expression w6x+5y3z for w=4,x=34,y=12 and z=1.25.


w6x+5y3z=46(34)+5(12)3(1.25)Substitute w=4,x=34,y=12 and z=1.25=4+92+5(12)3(1.25)Multiply=4+92+523(1.25)Multiply=4+92+52154Multiply=164+184+104154Get the LCD=344+104154Add=444154Add=294Subtract

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