Estimate a student's score on a Biology test two years after he got a score of 80 on a test covering the same material, by using Ebbinghaus' Law of Forgetting. Assume that c=0.3 and t is measured in months.
logP=log=P0−clog(t+1) Model
Solving for P
logP=logP0−log(t+1)2Law of Logarithm loga(AC)=ClogaAlogP=logP0(t+1)2Law of Logarithm loga(AB)=logaA−logaBP=P0(t+1)2Because log is one-to-one
Here P0=80,C=0.3 and t is measured in months
In two years: t=24 months
and
P=80(24+1)0.3P=30.46
The student's expected score on Biology test after 2 years is 30.46.
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