Check if $F$ is a continuous function of $r$ for the gravitational force $
\displaystyle
F(r) = \left\{
\begin{array}{c}
\frac{GMr}{R^3} & \text{ if } & r < R\\
\frac{GM}{r^2} & \text{ if } & r \geq R
\end{array}
\right.
\quad
$
exerted by the earth on a unit mass at a distance $r$ from the center of the planet.
Where $M$ is the mass of the earth, $R$ is its radius and $G$ is the gravitational constant.
Based from the definition of continuity,
The function is continuous of at a number if and only if the left and right hand limits of the function at the same number is equal. So,
$
\begin{equation}
\begin{aligned}
\lim \limits_{r \to R^-} \frac{GMr}{R^3} &= \lim \limits_{r \to R^+} \frac{GM}{R^2}\\
\frac{GM\cancel{(R)}}{R^{\cancel{3}}} & = \frac{GM}{(R)^2}\\
\frac{GM}{R^2} &= \frac{GM}{R^2}
\end{aligned}
\end{equation}
$
Therefore,
$F$ is a continuous function of $r$.
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