Determine an appropriate viewing rectangle for the equation y=0.3x2+1.7x−3 and use it to draw the graph.
We can determine the appropriate viewing rectangle easier by getting the x and y-intercept at the equation. So, if we set y=0
0=3x2+1.7x−3Divide both sides by 0.30=x2+173x−10Solve for xx=−17+√6496 and x=−17−√6496
Thus, the x-intercepts are at (−17+√6496,0) and (−17−√6496,0)
Or (1.4126,0) and (−7.0792,0)
Next, solving for y-intercept, where x=0
y=0.3(0)2+1.7(0)−3y=−3
The y-intercept is (0,−3)
Thus, we set the appropriate viewing rectangle to be [−10,5] by [−6,10]
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