Friday, October 19, 2018

College Algebra, Chapter 2, 2.3, Section 2.3, Problem 14

Determine an appropriate viewing rectangle for the equation y=0.3x2+1.7x3 and use it to draw the graph.

We can determine the appropriate viewing rectangle easier by getting the x and y-intercept at the equation. So, if we set y=0

0=3x2+1.7x3Divide both sides by 0.30=x2+173x10Solve for xx=17+6496 and x=176496

Thus, the x-intercepts are at (17+6496,0) and (176496,0)
Or (1.4126,0) and (7.0792,0)

Next, solving for y-intercept, where x=0

y=0.3(0)2+1.7(0)3y=3


The y-intercept is (0,3)
Thus, we set the appropriate viewing rectangle to be [10,5] by [6,10]

No comments:

Post a Comment