What is the probability that a 13-card bridge hand consists of all cards from the same suit?
There are $C(52,13)$ possible 13-card bridge hands. In which only four are of one suit. The chances of being dealt a hand of 13-cards of the same suit are
$\displaystyle \frac{4}{C(52,13)} = \frac{4}{635,013,559,600} = \frac{1}{158,753,389,900}$
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