Given
y=(1/3)x
it is in the form y=mx
where m=tan(theta)
tan(theta)=1/3
cot(theta)=1/tan(theta)=3
sec(theta)=+-sqrt(1+tan^2(theta))=+-sqrt(1+1/9)=+-sqrt(10)/3= -sqrt(10)/3 (in third quadrant)
cos(theta)=1/sec(theta)= -3/sqrt(10)
sin(theta)=+-sqrt(1-cos^2(theta))=+-sqrt(1-9/10)
= - 1/sqrt(10) (in the third quadrant)
csc(theta)=1/sin(theta)= -sqrt(10)
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