Determine the slope and $y$-intercept of the line $\displaystyle \frac{-3}{4}x + \frac{1}{2}y = 0$. Graph the line, labeling any intercepts.
We write the equation $\displaystyle \frac{-3}{4}x + \frac{1}{2}y = 0$ in slope intercept form to find the slope. We get
$
\begin{equation}
\begin{aligned}
\frac{-3}{4}x + \frac{1}{2}y =& 0
&& \text{Given equation}
\\
\\
\frac{1}{2}y =& \frac{3}{4}x
&& \text{Add } \frac{3}{4}x
\\
\\
y =& \frac{3}{2}x
&& \text{Multiply both sides by } 2
\end{aligned}
\end{equation}
$
The slope is $\displaystyle \frac{3}{2}$. To find the $y$-intercept, we let $x = 0$ and solve for $y$. So we have
$
\begin{equation}
\begin{aligned}
y =& \frac{3}{2} (0)
\qquad x = 0
\\
y =& 0
\end{aligned}
\end{equation}
$
The $y$-intercept is .
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