Create an input-output table that includes the limit limx→12−√x+3x−1.
Start with ΔTbl=0.1 and then go to 0.01,0.001 and 0.0001. When you think you know the
limit, illustrate the function and use the TRACE feature to verify the answer.
With ΔTbl=0.1
x2−√x+3x−10.7−0.2540.8−0.2530.9−0.2511.0ERROR1.1−0.2481.2−0.2461.3−0.245
With ΔTbl−0.01
x2−√x+3x−10.97−0.250.98−0.250.99−0.251.0ERROR1.01−0.2491.02−0.2491.03−0.249
Based on the values from the table, it seems that the
limx→1=−0.25 or −14
Then, by graphing f(x)=2−√x+3x−1, we have
We can see from the graph that the limx→1f(x)=−0.25
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