Solve [−(y4−y2+1)−(y4+2y2+1)]+(3y4−3y2−2)
Remove the parentheses that are not needed from the expression.
−(y4−y2+1)−(y4+2y2+1)+3y4−3y2−2
Multiply −1 by each term inside the parentheses.
−y4+y2−1−(y4+2y2+1)+3y4−3y2−2
Multiply −1 by each term inside the parentheses.
−y4+y2−1−y4−2y2−1+3y4−3y2−2
Since −y4 and −y4 are like terms, subtract y4 from −y4 to get −2y4.
−2y4+y2−1−2y2−1+3y4−3y2−2
Since −2y4 and 3y4 are like terms, subtract 3y4 from −2y4 to get y4.
y4+y2−1−2y2−1−3y2−2
Since y2 and −2y2 are like terms, add −2y2 to y2 to get −y2.
y4−y2−1−1−3y2−2
Since −y2 and −3y2 are like terms, subtract 3y2 from −y2 to get −4y2.
y4−4y2−1−1−2
Subtract 1 from −1 to get −2.
y4−4y2−2−2
Subtract 2 from −2 to get −4.
y4−4y2−4
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