Determine dydt if y=13u5−7 and u=7t2+1.We have dydt=dydu⋅dudtwithdydu=(3u5−7)⋅ddu(1)−1⋅ddu(3u5−7)(3u5−7)2 and dudt=7ddt(t2)+ddt1=−15u4(3u5−7)2=14tThus,dydt=−15u4(3u5−7)2⋅14t=−210tu4(3u5−7)2=−210t(7t2+1)4[3(7t2+1)5−7]2Substitute 7t2+1 for u
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