Tuesday, October 10, 2017

Intermediate Algebra, Chapter 2, 2.2, Section 2.2, Problem 6

Solve $P = a + b + c$ for $b$.

a.) For $b$


$
\begin{equation}
\begin{aligned}

P =& a + b + c
&& \text{Given equation}
\\
P - a - c =& a + b + c - a - c
&& \text{Subtract each side by $(a+c)$}
\\
b =& P - a - c
&& \text{Solve for $b$}

\end{aligned}
\end{equation}
$


b.) For $c$


$
\begin{equation}
\begin{aligned}

P =& a + b + c
&& \text{Given equation}
\\
P - a - b =& a + b + c - a - b
&& \text{Subtract each side by $(a+b)$}
\\
c =& P - a - b
&& \text{Solve for $c$}

\end{aligned}
\end{equation}
$

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