Tuesday, July 18, 2017

sum_(n=2)^oo lnn Determine the convergence or divergence of the series.

To evaluate the series sum_(n=2)^oo ln(n), we may apply the divergence test:
If lim_(n-gtoo) a_n != 0 then sum a_n diverges.
From the given series sum_(n=2)^oo ln(n) , we have a_n=ln(n) .
Applying the diveregence test,we determine the convergence and divergence of the series using the limit:
lim_(n-gtoo)ln(n) = oo
 When the limit value  (L) is oo then  it satisfies lim_(n-gtoo) a_n != 0 .
 Therefore, the  series sum_(n=2)^oo ln(n) diverges.
We can also verify this with the graph: f(n) = ln(n) .

As the value of n increases, the function value also increases and does not approach any finite value of L. 

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