Saturday, May 20, 2017

Intermediate Algebra, Chapter 4, 4.2, Section 4.2, Problem 42

Solve the system of equations 4x+y2z=3x+14y12z=342x+12yz=1. If the system is inconsistent or has dependent equations, say so.

Multiplying each side of equation 2 by 4 gives equation 1, so these two equations are dependent. Equation 1 and equation 3 are not equivalent, however, multiplying each side of equation 3 by 12 does not give equation 1. Instead, we obtain two equations with the same coefficients, but with different constant terms. Thus, the system is inconsistent and the solution set is \cancel0.

No comments:

Post a Comment