Saturday, May 13, 2017

Calculus and Its Applications, Chapter 1, 1.7, Section 1.7, Problem 32

Differentiate f(x)=(2xx2+1)3.



f(x)=3(2xx2+1)2ddx(2xx2+1)f(x)=3(2xx2+1)2[(x2+1)ddx(2x)2xddx(x2+1)(x2+1)2]f(x)=3(2xx2+1)2[(x2+1)(2)2x(2x)(x2+1)2]f(x)=3(2xx2+1)2[2x2+24x2(x2+1)2]f(x)=3(2xx2+1)2[22x2(x2+1)2]f(x)=3(2x)2(22x2)(x2+1)2(x2+1)2f(x)=12x2(22x2)(x2+1)4

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