Thursday, April 13, 2017

College Algebra, Chapter 4, 4.2, Section 4.2, Problem 22

Sketch the graph of polynomial function P(x)=14(x+1)3(x3) make sure the graph shows all intercepts and exhibits the proper end behaviour.
The function has an even degree 4 and a positive leading coefficient. Thus, its end behaviour is y as x and y as x.
To solve for the x-intercept, we set y=0.



0=14(x+1)3(x3)0=(x+1)3(x3)


We have,
x=1 and x=3

To solve for the y-intercept, we set x=0

y=14(0+1)3(03)y=14(1)3(3)=34

No comments:

Post a Comment