Tuesday, April 11, 2017

Calculus and Its Applications, Chapter 1, 1.7, Section 1.7, Problem 38

Differentiate h(x)=(13x27x)5.



h(x)=(27x13x)5Laws of Exponenth(x)=5(27x13x)4ddx(27x13x)h(x)=5(27x13x)4[(13x)ddx(27x)(27x)ddx(13x)(13x)2]h(x)=5(27x13x)4[(13x)(7)(27x)(3)(13x)2]h(x)=5(27x13x)4[7+21x+621x(13x)2]h(x)=5(27x13x)4[1(13x)2]h(x)=5(27x)4(13x)6

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