Tuesday, December 20, 2016

Single Variable Calculus, Chapter 2, 2.3, Section 2.3, Problem 17

Determine the limh0(4+h)216h, if it exists.


limh0(4+h)216h=h2+8h+\cancel16\cancel16h Expand the equation and combine like terms. limh0h2+8hh=limh0\cancelh(h+8)\cancelh Get the factor and cancel out like terms. limh0h+8=0+8 Substitute value of h and simplifylimh0(4+h)216h=8

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