Determine the limh→0(4+h)2−16h, if it exists.
limh→0(4+h)2−16h=h2+8h+\cancel16−\cancel16h Expand the equation and combine like terms. limh→0h2+8hh=limh→0\cancelh(h+8)\cancelh Get the factor and cancel out like terms. limh→0h+8=0+8 Substitute value of h and simplifylimh→0(4+h)2−16h=8
No comments:
Post a Comment