Monday, December 12, 2016

College Algebra, Chapter 5, 5.4, Section 5.4, Problem 34

Solve the equation x210xx10x=2(10x)

x210xx10x=2(10x)10x(x2x)=2(10x)Factor out 10x\cancel10x(x2x)\cancel10x=2(\cancel10x)\cancel10xDivide both sides by 10xx2x=2Subtract 2x2x2=0Factor using trial and error (x2)(x+1)=0

Solve for x

x2=0x+1=0x=2andx=1

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