Thursday, December 1, 2016

Beginning Algebra With Applications, Chapter 5, 5.4, Section 5.4, Problem 14

Using the slope intercept form, determine the equation of the line that contains the point whose coordinates are $(-1,2)$ and has slope of $\displaystyle \frac{-1}{2}$.


$
\begin{equation}
\begin{aligned}

y =& mx+b
&&
\\
y =& \frac{-1}{2} x + b
&& \text{Replace $m$ with } \frac{-1}{2}
\\
2 =& \frac{-1}{2} (-1) + b
&& \text{Substitute $x = -1$ and $y = 2$}
\\
2 =& \frac{1}{2} + b
&& \text{Solve for } b
\\
\\
\frac{3}{2} =& b
&& \text{Add } \frac{-1}{2}
\\
\\
y =& \frac{-1}{2} x + \frac{3}{2}
&& \text{Write the equation of the line by replacing $m$ and $b$ in $y = mx+ b$ by their values}

\end{aligned}
\end{equation}
$

No comments:

Post a Comment