Find an equation of the line that pass through (12,−23) and perpendicular to the line 4x−8y=1.
If the line is perpendicular to 4x−8y=1, then its slope is equal to the negative reciprocal of the other.
4x−8y=18y=4x−1Add 8y and subtract 1y=48x−18Divide by 8y=12x−18
By observation, the slope of the line perpendicular line to 4x−8y=1 is m=−2.
By using Point Slope Form
y=mx+by=−2x+bSubstitute m=−2−23=−2(12)+bSolve for b−23=−1+bSimplifyb=13
Thus, the equation of the line is..
y=−2x+13
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