Tuesday, May 17, 2016

Single Variable Calculus, Chapter 3, Review Exercises, Section Review Exercises, Problem 28

Find y of y=13x+x



y=ddx(13x+x)y=(3x+x)ddx(1)(1)ddx(3x+x)(3x+x)2y=(x+x)13ddx(1)(1)ddx(x+x)13(3x+x)2y=(x+x)13(0)(1)(13)(x+x)23ddx(x+x)(x+x)23y=13(x+x)23(1+12x)(x+x)23y=(2x+1)3(2x)(x+x)23(x+x)23y=(2x+1)6x(x+x)43

No comments:

Post a Comment