Thursday, February 18, 2016

College Algebra, Chapter 1, 1.4, Section 1.4, Problem 28

Evaluate the expression (23+12i)(16+24i) in the form of a+bi.


=(23+12i)(16+24i)=(23)(16)+23(64i)+12i(16)+(12i)(24i)Use FOIL method=19+128i3+2i+288i2Evaluate=19+128i3+2i+288(1)recall that i2=1=(19288)+(1283+2)iCombine like terms=25919+1343iSimplify

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