Friday, January 1, 2016

Beginning Algebra With Applications, Chapter 3, 3.2, Section 3.2, Problem 126

Solve 5n+3=2n+1 and check.


5n+3=2n+1Given equation5n2n=13Subtract 2n and subtract 3 to each side3n=2Simplify\cancel3n\cancel3=23Divide by 3n=23


Checking:


5(23)+3=2(23)+1Substitute n=23103+3=43+1Simplify13=13

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